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[savek]

I support my thesis cio? if you just leave them original

[munro]

guys who's? the formula to calculate, or better to convert the microseconds in degrees crankshaft?
let me explain, if I have for example an injector which opens to 594 microseconds how can I quantify how many degrees of rotation the motor match?

[franco75]

Degrees=rev/min*6*T
Es: 584 µsec at 3000 rpm
Degrees = 3000*6*584/1000000 = 10.5 degrees

[cicciogsr]

bravo ? right.. we get cos?...rpm*360=(grad/min)/60000000=(grad/ms)*.t(ms)=degrees

maybe ? pi? simple to understand

[munro]

thank you frank...I know cos? that T=1000000?? evisto you're at it, can you explain to me a moment, this formula??
Thanks

[munro]

bravo ? right.. we get cos?...rpm*360=(grad/min)/60000000=(grad/ms)*.t(ms)=degrees

maybe ? pi? simple to understand

ciccio cos? the.t?

[cicciogsr]

the time to insert it in the formula

[munro]

I am, however, a half-idea I made also on the basis of you have injection times and the cio? if at 4000 rpm I have a time of injection
of 795us to know how long the degree opens the injector to do this calculation 4000X360?degrees=1440000 these are the degrees in a minute in a second I to do? 1440000/60=24000 degrees per second now in order to know how many degrees do? the motor according to the injection time lighthouse 24000/795=30? degrees... what about pu? be feasible?

but this calculation and trusted??

[cicciogsr]

to the eye, and the cross, it seems to me.. are there more? 10 degrees error

[franco75]

thank you frank...I know cos? that T=1000000?? evisto you're at it, can you explain to me a moment, this formula??
Thanks

I divide by 1000000 if I put the time in microseconds