the calculation seems to me plausible
the calculation seems to me plausible
nice job gionag , but I can not figure out how to use that table why? if I fixed a number of laps, and I'm going to see in the map of the SOI for that value of laps I was 16 bits that indicate the behavior in the various requests of diesel...now how do I decide which the value of the rail I have to take from the table, what have you done ? I don't know if I managed to understand my doubt
guys anyone found solutions ? I do not come to**** more? I am looking for a solution, and more? I incasino
it seems to me that you have made a speech a little confused in your request.
in the table shown has nothing to do with the SOI, the rail pressure, that only serves to calculate the duration of injection in degrees crankshaft.
ask again
Sorry, I realize that I will explain as a book bargain.... I understand better what I would like to follow from the knowledge of these maps... Since my goal ? inject ir? diesel fuel than stock (100 mm3) I would like to know when starts the injection and how long is it in order to be able to calculate how many degrees of post injection I and if ? the case, anticipate.... This speech nn I can do why? the map and SOI map duration does not have the same parameters of the X-axis ? Y, and so I can not compare them to understand, for example, at 3000 rpm when it starts the injection and how long it lasts... I don't know if I explained it well
according to me, the titanium already? I'll say...
then, however, in the axis of the soi you have the rpm
you have so many degrees quant'? the iq.....
a p? logic then is not bad...
you can't expect to inject 80mm3 to 800 rpm...
c'? a proportion.....
A rider does not create queues even in the car...
a automoblista create queues even on a motorcycle...
munro I agree that I will never inject 80mm3 to 800 rpm ...but ? a limit of the pump, a rail that those laps nn can provide high pressures, right ? ? this is the proportion of which you speak ?
however, even if I have read it 100 times what you wrote I still do not find relationships to do the calculation that I said before...sorry if I'm so blunt, but I'd really like to learn
the first problem to solve ? :
given an injection pressure, and set the IQ to be injected, how long should I keep open the injectors ?
at this point, you will have a time in the us, the time in the us the convert as a formula for the number of laps you want to know the duration in degrees.
of course, given a fixed time (time of injection), the angle that the crankshaft turns during the opening varies according to the rpm, of course, make? less degrees at high rpm and vice versa.
example (with data totally invented).
I have to inject 100mm3, this brings me to a time of injection with 1400bar of 1200us.. then I convert 1200us in degrees in relation to different rpm (to get some points of reference for the mid-bass high rpm). you will find that at 2000 rpm 1200us, the equivalent of 30? to 3000rpm 20? and to 4000rpm 10?.
now it occurs, by subtracting the advance payments (which you find in relation to the rpm in a direct manner, without the need to convert).
from them, you understand how much you are out and where to possibly anticipate.
NOW, as I always say, these are my guesses, perhaps without foundation... I'm taking you back just as I realized I
I tried to make a real account with the procedure you described...then I found that to 3000 rpm and 1400 bar to inject 70mm3 want us 877 us, the equivalent of 15.7 ? .... now the map SOI tells me that those rides and those mm3 my injection begins 8.8? before TDC ...then the degrees of post-injection 6.9? ....? right ? I figured out how to do ?
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