change advances

[cicciogsr]

bravo ? right.. we get cos?...rpm*360=(grad/min)/60000000=(grad/ms)*.t(ms)=degrees

maybe ? pi? simple to understand

[munro]

bravo ? right.. we get cos?...rpm*360=(grad/min)/60000000=(grad/ms)*.t(ms)=degrees

maybe ? pi? simple to understand

ciccio cos? the.t?

[munro]

thank you frank...I know cos? that T=1000000?? evisto you're at it, can you explain to me a moment, this formula??
Thanks

[franco75]

thank you frank...I know cos? that T=1000000?? evisto you're at it, can you explain to me a moment, this formula??
Thanks

I divide by 1000000 if I put the time in microseconds

[cicciogsr]

the time to insert it in the formula

[cicciogsr]

to the eye, and the cross, it seems to me.. are there more? 10 degrees error

[franco75]

I'm not good with explanations, but I try:
divide the rpm by 60 to get revolutions per second, and then multiplied by 360 to get the degrees aal second, then divide by 60 and multiply by 360 ?
how to multiply to 6.
had any of the degrees / second multiply by the seconds, and get the degrees.
In the case of the example of mcjtd, or 795 us to 4000 g/m is the duration ? 19?

[Chris156]

I'm not good with explanations, but I try:
divide the rpm by 60 to get revolutions per second, and then multiplied by 360 to get the degrees aal second, then divide by 60 and multiply by 360 ?
how to multiply to 6.
had any of the degrees / second multiply by the seconds, and get the degrees.
In the case of the example of mcjtd, or 795 us to 4000 g/m is the duration ? 19?

precisely 19,08?

[munro]

ok understood, thanks...now let's put the case that we,also, depending on the file posted by ciccio of jtd 105,we have the greatest tinj that ? of 1151us and we have to 1350 bar to press an iq of 70mm3 at 4000 rpm with the maximum advance that ? 21?..ok?
then, the calculation and 4000*6*1151/1000000=27,6 degrees of duration of injection, and as this begins to 21 degrees ppms end to 6.6 degrees dpms....
now assuming that I want to inject 85mm3 to? (radiceq of 1350*1151)/70=604 then 604*85/radiceq 1350=1397us
and then the new duration of injection in degrees sar? 4000*6*1397/1000000=33,5 degrees if I rest with the beginning of the injection to 21? in this case, inquire to inject 12.5? dpms that ? twice as much as expected, the manufacturer then surely I'll fumosit? temperatures and egt to the stars...and then if I wanted to return this value in the standard, I have to anticipate a p? the injection back in my "time window" and return to the 6? in most of the dpms to the ppms also to comply with the percentage of injection of 76/24% based on the pms that mom fiat has decided...

[dvdtuning]

Then you should give 6? of advance?