Then Joseph... Pass in behind, and we clearly..
Formula to find the degrees of advance:
RPM/60/1000000x360= degrees per microsecond (the factor mentioned before)
degrees per microsecond x times on IQ (ori or increased according to what you want to do that you can find on the pressure expressed in microseconds ) = degrees of duration
When you calculate this, you must make a comparison between ORI and MOD and see how many degrees go in the post and try to get the injection.
Live ****** & you Die a HERO !
Tranky the formula that I have used is rpm*360* Tiny /60000000 I get so the duration in liked it. By subtracting the degrees of advance I comes out how many degrees I ends l injection... so far everything is ok. The problem I have is that in the map the times I have the bp for certain values of rail pressure (e.g. 800 bar ) if I but I moddato map rail raising and then the pressures on IQ I will have to, consequently, shorten the time, right? We put the case that the rail pressure the is increased from 800 to 1000 bar how do I organize the Tiny? For the values that I've already used in the map ori (for example 1600 bar) use the formula found here in a post that has the seguentè Tiny = (IQ*(K)/square root Prail
This, however, after having calculated the factor K for that curve (1600 bar in this case), and I calculate it the tiny to the new iq,but for 1650 bar how do I calculate them? In percentage, it seems to me too approximate, or am I wrong?
As soon as I can I create a table so maybe it is more easy to explain. In practice, I do not understand how to adjust the timing so "precise" to the new pressure rail on the iq set in the map rail
The time is always on the increase on the IQ new and do not change.
The advances in the li calculations in the formula.
Then a fattorencome told you above calculations the new IQ advances on the basis of the new p.rail.
Make the table that is easier to understand also
Live ****** & you Die a HERO !
Hello tranky I enclose the table of calculations that I made inspired by one that I sent some time ago...for now I have only left the values of gold and I reported the values I managed to calculate, leaving the empty boxes for the data that I still can't ricavarmi...or the new times on the Prx rail increased. Calculations delta.rar
I forgot,in one of the sheets in the file I made of the examples of the calculations for the new iq calcolandomi the K-factor for the curve and for calcolarmi the new tiny but the pressures increased I don't know how to move
The formula to remember here so it is easier to make calculations of comparison,premising that I write literally "square root"instead of srqt in order not to confuse any person,as well as the symbol " x "to indicate a multiplication instead of the symbol "*".
k=(the square root of the prex rail) x tinj/Qi
Oi=(square root of the prex rail) x tinj/k
Tinj=(Qi x k) : square root of the prex rail.
Taking the example of a edc15c6 tells me that the curve ori corresponding to 1350bar that the duration is Us1230 to 70mm3,obviously the injectors are original.
then,
k=(square root of 1350) x 1230/70=645,61551..
Qi=(square root of 1350) x 1230/645,61551..
Tinj=(70 x 645,61551...) : (the square root of 1350bar)=1230
Now,to equal the k-factor, and rail pressure,is that I use the formula,whether I face proportion, the result does not change.I have always a linear increase.
Formula :
T inj= (85 x 645,61551..) : square root of 1350=1493,..(In the formula, we see that the only information that varies is the amount of the mm3 of fuel,then mathematically will be a proportion as a (85 :70) x 1230=1493,..as it is.
A rider does not create queues even in the car...
a automoblista create queues even on a motorcycle...
Munro I tried the formulas as you defined, but does not return anything...Originally Written by munro
then.. I try to calculate K (I assume you meant advances with a K) then I:
QI static = 100mm3
so here the calculation only in the column of the new IQ of the bp changed without the other iq at the moment and I calculate the time and the rail pressure
Tinj on prx.rail set in the table:
1000bar = 1394.8
1150bar = 1311.2
1300bar = 1220.4
1450bar = 1126
1500bar = 1062.53
1600bar = 1030.8
1700bar = 995
1800bar = 959.2
then having this can I:
prx.rail on rpm
1500rpm = 1114
1750rpm = 1229
2000rpm = 1343
2250rpm = 1457
2500rpm = 1571
3000rpm = 1686
3500rpm->5000rpm = 1800 (here the value is static to 1800bar by 3500rpm at the end of the scale)
to 1500bar, k = (rq 1500) x (1062.53/100)
38.72 x 10.62 = K = 411.41 <-- seems to count as a value, no?
at this point xo if I divide instead of multiply, I get:
38.72 : 10.62 = K = 3.64 <-- 1500rpm ori 1.8 on 70mm3 I would say that seems correct..
It is the wrong formula or something is missing to calculate the advance payments ?
Live ****** & you Die a HERO !
Thank you munro for the intervention,this is the formula that I use I also a parity of rail pressure, but let's say for the example you posted we decide to change the rail pressure, bringing it from 1350 to 1500 bar, we now know that the T iny for the 85 mm3 is equivalent to 1493 us, but raising the rail pressure as the recalculation of the whole? By changing the map-rail, do I have to change the timing? Even if theoretically them I'd let ori?
I'm sorry I wasn't at the pc and I did a little confusion,let me explain better. I'm calculating the duration and I used the following formula : rpm*360* Tiny /60000000 .
Here's an example, calculating the duration for the maximum iq that is 70 mm3 4,000 rpm. Then multiplies
4000 x 360 x 923 / 60000000 = 22.15 °
Obviously, 923 are the us that I have in the map times to 1600 bar and 70 mm3,having that pressure rail map rail for that iq and rpm.
Redoing the same calculation for the 2500 Rpm I find myself in the map rail, and a pressure of 1450 bar,the pressure in the map the times I have not, but I find myself 1400 bar... I Know that the ecu interpolates and, if obtained, if the us needed to that prx rail but I dovendomi calcolarmi advances like I need to move? In this case I have parameters very similar between 1400 and 1450 bar,but in different cases? How to calculate the correct duration, and consequently, the advances? For 1400 bar need 987 us mind for 1450? This is the problem
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