you're not very far from 5nm>mm3 with your calculation 400nm/97mm3=4.2 nm-mm3...
in addition, in the ecu there is a map that subtracts nm then iq for the internal calculation of the friction is located immediately after the torque limiters and an 8x8 z axis all in negative...
A rider does not create queues even in the car...
a automoblista create queues even on a motorcycle...
Sorry if I take advantage of your expertise, but this map is also present in the EDC16c8? I still can't download the files, and what I have on hand that I'm studacchiandoci a little on is only this.Originally Written by munro
you edc16c8 and c39 are very similar.
A rider does not create queues even in the car...
a automoblista create queues even on a motorcycle...
As you rightly said, even if the fuel theoretically has a stoichiometric ratio of 14.5:1 in those relationships will never burn well, and sophomore alex len chipped in like a chimney.
However, I would like to add a little of use to see if I have understood well.
Let's say that the MAF sensor will show a value of 630 mg/cycle at 2000 rpm and then trying it in the map, fumes or lamdba, the corresponding value is 1330, I'm talking about a unit EDC16c, the calculation that results is 1.33*14,5=19,285 and, therefore, if I divide 630 to 19,285 = 32,67 are already mm3 not mg of diesel oil as spiegavi in your post previous to this one that I mentioned.
All of this implies that the ratio of the air/fuel, or AFR, in reality, is not 19,285:1 as you might think, but one must keep in mind one thing or the weight of the diesel fuel injected and not its volume otherwise comparing a weight with a volume and it's like comparing potatoes with carrots.
The air we already know very well how much it weighs because the work had already been done by the MAF sensor, the fuel should calcolarcelo, and then multiplying the 32,67mm3 for 0,8325 (average between 0,820 and 0,845, which is the density that should have by law the diesel) I get about 27,2 mg that compared with the amount of air I get a AFR of 21.3.
wrong...if you split the mg air to the afr resulting from the calculation always mg then the weight of the diesel.
the edc16c work in mm3 then the volume to convert the fuel oil in mg per mm3 of the usa the conversion is 0.85.
A rider does not create queues even in the car...
a automoblista create queues even on a motorcycle...
Of course, you're right. I agree with you.
I think I have it bad post the question, I'll explain the doubt that I had come.
You talk about the fact that the units EDC16c work in mm3, and then I thought that in the value the place on the map, the flue gas is equal to 1330 is already contained in the conversion of 0.85 to get to the end of the calculation you have already the converted value in mm3, we say a value is ready for use.
So my reasoning was, if a unit let's say “u” starting from the value MAF 630 and lambda let's say for example 1,565 the calculation done is 630/(14,5*1,565)=27,66 that are mg and then if I want to get the mm3 I divide everything by 0.85 and I get 32,67mm3 because you said that these units work in mg.
While I thought that in a control unit “c”, the programmer had already done a sort of fix then you have already divided 1,565 by 0.85, and then put it in the map, 1,330, which is the result of this division in such a way that the dividend is always the famous 630 mg (14,5*1,33) I get immediately 32,67 already converted to mm3.
I have little time today and tomorrow but I...I all and 2 in the machines of the family these ecu's and the c8 differs from the c39 for the dpf I think.
400cc air-x 1.293 = 517.2 mg of air are in the cylinder. Now I said that to 68mg (=80mm3) x14.7 = 999.6 the mg of air necessary to maintain the afr. 999.6/517.2 = 1,92 bar of pressure necessary to compress 999.6 mg of air in the cylinder. If the turbine ori holds this pressure, we can begin to moddare maps turbo giving it this limit. If we do not do a step at a time is the map we end up in 2020....and there we can star all day on the forum....
in essence, the calculations are fine up to a certain point.
beyond this,experience, policy,knowledge,etc...
1.9 bar+1 atmo are really a lot for a gt1544v ori..
A rider does not create queues even in the car...
a automoblista create queues even on a motorcycle...
Whereas, as it says munro relying on the MAF is the best solution, according to me you can sketch out a rough estimate.
I agree that a cylinder of 400cc filled to the entire atmospheric pressure contains 517 mg of the air, if we apply to the calculation of a VE of 80%, we get about 414mg (400*0.8*1.293).
According to me it is not conceivable to burn the diesel at the ratio stechio of 14.7:1, but always according to my opinion it is more prudent to get a 17:1 maybe 18:1, however, I would try first with 17 and then I would see if the amount of smoke is acceptable.
In this case 68*17=1156mg divided for 414 damage about 2800 absolute pressure (1000+1800) always turbine permitting.
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