The amount of diesel and smoke

[explode82]

Hello eplode82, I'm confusing, I only asked a question, obviously, more bar in the rail is equivalent to more quantity of diesel.
My question was on how I could increase the performance when I get to 1000 rpm .
In my case I noticed improvements only by increasing the injection times and not from the map fumes or pedal or couple.
I asked myself the question if the pump is taking a long time to raise the pressure to give what I ask from the pedal.

then 1000 rpm ? a p? difficult of performance,starting from the pedal,it at low rpm ? already very high as a request for the rail,that very much depends on the mechanics,in the sense that the pumps are driven by a motor,such as for example the pump of the rail that is located on the 1.3 mjt that ? operated by the camshaft,and to give certain pressure needs a certain njumero of laps, and just for fairness the most? rail not from pi? diesel,it is more useful to fill the flute under the au request massive diesel.........with this I think I've given you the answer pi? that specific on what you wanted to know

[munro]

Alessandro....
I did not understand what you I should explain...
if you continue to return to my post but I do not ask a specific question....
I think we can stay here for the purposes of the new year....

[lupak]

Thanks for the reply explode82, in the peugeot 2.0 hdi pump to the rail ? electric, doesn't it ? driven from the camshaft. To fill the flute in the peugeot there is a map called "Rail pressure precontrol value", which indicates the position of the valve that regulates the amount of diesel fuel that falls into the tank.
Then at the same time of injection with increased rail I have the same amount of fuel ?

[munro]

in the pegeout hdi the high pressure pump of the common rail and is operated by the timing belt...
and by the masimo 1350-1400bar..
you maybe lupak you confused with the electric fuel pump low pressure fuel-feed pump of the common rail...
in this case, the pressure read you to 7300bar in reality and refers to the low pressure and ? the millibar..or 7300 millibars, corresponding to 7.3 bar....
I would also say to explode82 that his statement..where he says that most rail not more diesel and totally wrong!!
if so, the additional electronic devices, which are fitted on the sensor and press the rail and serving to increase the press ingannado the ecu with a signal lower, so that the ecu reacts by increasing the press,would have no way to exist
so back to answer lupak equal to the opening time of the injector for es 560us with the rail to 700 bar injection for es 50mm3 of diesel...if the port rail to 1400 bar with always 560us opening the injector as diesel fuel in most injection???

[munro]

I would add that you need to know the flow rate of an injector does not ? proportional to the pressure variation,the flow rate increases with the square root of the pressure increase...then double the rail pressure does not equate to double the flow injector, but "only" to 1/4...
the formula ?:flow2=flow1*sqrt of press1/press2....
sqrt=square root...
press1=700bar
press2=1400bar
flow1 in this calculation and 50mm3
flow2 and the new port injector with the press2...
to you the conclusions....

[lupak]

I would add that you need to know the flow rate of an injector does not ? proportional to the pressure variation,the flow rate increases with the square root of the pressure increase...then double the rail pressure does not equate to double the flow injector, but "only" to 1/4...
the formula ?:flow2=flow1*sqrt of press1/press2....
sqrt=square root...
press1=700bar
press2=1400bar
flow1 in this calculation and 50mm3
flow2 and the new port injector with the press2...
to you the conclusions....

flow2 = 50*sqrt(700/1400)
flow2 = 50*sqrt 0,5
flow2 = 50* 0,7=35,35

C' ? something that should not be !!!
Maybe we need to do ; flow2=flow1*sqrt of press2/press1
and if so,
flow2=50*sqrt (1400/700)= 50*sqrt 2= 50*1,41= 70,7

[cicciogsr]

I would add that you need to know the flow rate of an injector does not ? proportional to the pressure variation,the flow rate increases with the square root of the pressure increase...then double the rail pressure does not equate to double the flow injector, but "only" to 1/4...
the formula ?:flow2=flow1*sqrt of press1/press2....
sqrt=square root...
press1=700bar
press2=1400bar
flow1 in this calculation and 50mm3
flow2 and the new port injector with the press2...
to you the conclusions....

Munro-I'm sorry, can you explain the formula of the
Pressure?

[lupak]

Thanks Munro for these explanations, I see that you're very well with the theory and mathematical formulas;
With regard to the pump you are right, I am confused with pressure and low pressure.
The 7300 bar read them from the map rail mod.
From what I have written, I realized that the high-pressure pump at 1000 rpm can give pressures only and that if I would like to increase the performance will be able to do so only with the map of the injection times.

[tezzero]

From tests made at the tour any common rail pump bosch both with pumping units from 6,5 mm to 7 mm is able to reach approximately 2000 bar of pressure, with the injectors at maximum load at around 1300 rpm the pump then 2600 motor..the pump delphi pushes a p? pi?

[lupak]

Sorry tezzero but not me ? clear what you have written.
The common rail is not coming to 1350 bar ?