How to recognize the maps of ecm titanium

[tranky]

Look what we pulled out all this pappardella accounts because at the beginning of the topic you have rightly said to begin examining the AFR. From there, we suggested to make a map of 80 mm cubes. Then we started from the map lambda To inject 80 without smoking over due. Not to smoke you have to give him the air right then you know the turbo pressure needed. Found this as in the calculations above switing as you start the map the turbo with those data. Then you go to look for the lim iq out of drivers, to adapt them to 80mm3, it informs the ecu using the Bp of all the maps that the new iq max is 80, and adjusts the pedal to the request using the map conversion nm-iq. Of course, if you hope to make it in a day....through the forum, I repeat it is a must that one changes the map step-by-step through the info that come out reasoning all together for comparison. Time ****** of all permitting.

Friend with the summary you have made the idea of the procedure request pre-ecm I have done above.
Was what was missing in the speeches made that, for those who like you knows how to do is taken for granted, for people like me who there is inside is not at all obvious.
Told the ioc we continue to study and not give up!
I try to follow you and post something as soon as possible that I want to assimilate educational material as a blackhole!

[andrea80]

Great Munro

[munro]

I would like to add one thing to the post before, there is also another calculation that you can do to know exactly what pressure you have to compress the intake air as a function of the horses provided the theoretical and the bsfc...if you want to the place..

[andrea80]

Maybe... Is luggage interesting

[Errecinque]

if we are honest there is a way to know how much pressure it can support a turbo, but it is essential to have on hand and understand a compressor map
there is, however, a formula that from the air the hypothetical intake from the engine, we can extrapolate the iq and vice versa...
the formula is:CFM = L x rpm x VE x PR / 5660


L = Displacement
rpm = rpm
VE = volumetric efficiency
PR = pressure Ratio turbo
5660= equivalence ratio


"CFM" is a unit of measure of the anglo-saxon, "cubic feet per minute", and is used in some of the maps of the compressor.as well as lb/min which is going to pounds of air a minute.below are the conversions
CFM / 14.27 = lb / min
lb / 0,45359 = kg


however, some compressor-map are in m3 / sec then we have to convert from weight to volume.
the typical weight of the ambient air is about 1.2 kg / m3 at 20 degrees Celsius.


PR = pressure ratio with the addition of always 1 bar press atmospheric.
I repeat, however, is only a theoretical one, because here the variables that come into play are many.

so if we take for example a 6-cylinder engine 3.2 l(it is a mercedes engine, on which the stool some jobs) and we want to know how much air aspires to 4000 rpm is 1,65 bar of boost, lighthouse..


3.222 x 4000 x 96 x 2,65 / 5660 = 579,28 CFM = £ 40,59 / min = 18.41 kg / min = 0.306 kg / sec = 0.256m3 / sec
if you have under hand a compressor map you already have 2 coordinates for this transient.
now that sappaimo how much air sucks in and compresses theoretically, our engine, we can move on to diesel.


in the case of our engine that is a 6-cylinder 4-stroke(of course) we will have 3 strokes of combustion per revolution.
then at 4000 rpm we will have 4000 x 3/60 = 200 T / sec
T= injections/second.
knowing this, and knowing that the lambda we want to go to extrapolate the iq theoretical from the calculation is simple....
P. S: it is true they are calculations and concepts a bit heavy to digest, especially for those who is a novice with this stuff but if you understand these things, everything is more simple in the end.

Munro.....so I get excited!!!

[Errecinque]

Was what was missing in the speeches made that, for those who like you knows how to do is taken for granted

Watch sincerely I would know to do very little, it's just a passion that I have less than 2 years ago, I had been told I would have been able to open, read and write the ecu of my car I would have laughed out loud. I don't even know why the first time I gave a look to forum. From there it is taken the spring, and I did the same way what are you doing. Are only the party a bit before, but a lot of this road you will understand immediately that it is infinite and you never stop learning
and I have to say that when there is a user as a munro and all the gold that cola....

[tranky]

Watch sincerely I would know to do very little, it's just a passion that I have less than 2 years ago, I had been told I would have been able to open, read and write the ecu of my car I would have laughed out loud. I don't even know why the first time I gave a look to forum. From there it is taken the spring, and I did the same way what are you doing. Are only the party a bit before, but a lot of this road you will understand immediately that it is infinite and you never stop learning
and I have to say that when there is a user as a munro and all the gold that cola....

Know that t the respect you not only because you're the batman of critical situations, but also for the simplicity and the seeds form a professional that you have to give info while asking questions one is asking a question in the correct way and find out the answer that he sought.
Now back to the address of the file the ecu of this 1600...
I read in 2d practically ALL of the files by excluding the help of the Driver of the ECM and I found enumerevoli bp which I assume should be changed to the address of the 80mm3.. Ve them the list, and in the case discuss them if you put too many curves in the cauldron.
1Ec572 - 1ec622 - 1ed9ac - 1eeeb0 to 1eeeba - 1efd1e - 1f3f00 - 1f4aca - 1f4af2 - 1f4b2e - 1f4b42 - 1f4a4e - 1f4efe - 1f4ff2 - 1f50f2 - 1f5426 - 1f543a - 1f5562 - 1f5662 - 1f57ce - 1f58ce - 1f5a3a - 1f5bea - 1f5cb2 - 1f6132 - 1f6232 - 1faba6 - 1fb83e - 1fbab4 - 1fd44a
I'm almost certain many of these but some do not have the curve similar to the BP first of a series of maps are more to "pin" and I don't know if they are the drivers of that size or nothing do to with it..
Let me know if it is correct the analysis, or I shot to the american ('do cojo cojo).
Thanks

[munro]

post the link so that I forbear to "divert" too much of the discourse in the thread...
http://www.professionalchiptuning.ne...bo-vt9240.html

[tranky]

post the link so that I forbear to "divert" too much of the discourse in the thread...
http://www.professionalchiptuning.ne...bo-vt9240.html

Hats off friend!
Very good post..

[giuseppe89]

if we are honest there is a way to know how much pressure it can support a turbo, but it is essential to have on hand and understand a compressor map
there is, however, a formula that from the air the hypothetical intake from the engine, we can extrapolate the iq and vice versa...
the formula is:CFM = L x rpm x VE x PR / 5660


L = Displacement
rpm = rpm
VE = volumetric efficiency
PR = pressure Ratio turbo
5660= equivalence ratio


"CFM" is a unit of measure of the anglo-saxon, "cubic feet per minute", and is used in some of the maps of the compressor.as well as lb/min which is going to pounds of air a minute.below are the conversions
CFM / 14.27 = lb / min
lb / 0,45359 = kg


however, some compressor-map are in m3 / sec then we have to convert from weight to volume.
the typical weight of the ambient air is about 1.2 kg / m3 at 20 degrees Celsius.


PR = pressure ratio with the addition of always 1 bar press atmospheric.
I repeat, however, is only a theoretical one, because here the variables that come into play are many.

so if we take for example a 6-cylinder engine 3.2 l(it is a mercedes engine, on which the stool some jobs) and we want to know how much air aspires to 4000 rpm is 1,65 bar of boost, lighthouse..


3.222 x 4000 x 96 x 2,65 / 5660 = 579,28 CFM = £ 40,59 / min = 18.41 kg / min = 0.306 kg / sec = 0.256m3 / sec
if you have under hand a compressor map you already have 2 coordinates for this transient.
now that sappaimo how much air sucks in and compresses theoretically, our engine, we can move on to diesel.


in the case of our engine that is a 6-cylinder 4-stroke(of course) we will have 3 strokes of combustion per revolution.
then at 4000 rpm we will have 4000 x 3/60 = 200 T / sec
T= injections/second.
knowing this, and knowing that the lambda we want to go to extrapolate the iq theoretical from the calculation is simple....
P. S: it is true they are calculations and concepts a bit heavy to digest, especially for those who is a novice with this stuff but if you understand these things, everything is more simple in the end.

the boys then following the speech, and the formula of the great murno we should have for this 1.600 cc the following result:

CFM = L x RPM x VE x PR / 5660

1598 x 4000 x 95 (theoretical being 16v) x 2.7 (assuming 1.7 bar of turbocharger series) / 5660 = 289.67 CFM = 20.299 Lb / min =44.751 Kg/min =0.745 Kg/sec = 0.620 M3/ sec
in practice, this engine ingurgita to 2.7 bar of boost pressure (environment including) 620 cm3/sec
I hope not to be wrong in any calculation and I thank you infinitely murno for the valuable information!