How to recognize the maps of ecm titanium

[switing63]

wrong...if you split the mg air to the afr resulting from the calculation always mg then the weight of the diesel.
the edc16c work in mm3 then the volume to convert the fuel oil in mg per mm3 of the usa the conversion is 0.85.

Of course, you're right. I agree with you.
I think I have it bad post the question, I'll explain the doubt that I had come.
You talk about the fact that the units EDC16c work in mm3, and then I thought that in the value the place on the map, the flue gas is equal to 1330 is already contained in the conversion of 0.85 to get to the end of the calculation you have already the converted value in mm3, we say a value is ready for use.
So my reasoning was, if a unit let's say “u” starting from the value MAF 630 and lambda let's say for example 1,565 the calculation done is 630/(14,5*1,565)=27,66 that are mg and then if I want to get the mm3 I divide everything by 0.85 and I get 32,67mm3 because you said that these units work in mg.
While I thought that in a control unit “c”, the programmer had already done a sort of fix then you have already divided 1,565 by 0.85, and then put it in the map, 1,330, which is the result of this division in such a way that the dividend is always the famous 630 mg (14,5*1,33) I get immediately 32,67 already converted to mm3.

[switing63]

400cc air-x 1.293 = 517.2 mg of air are in the cylinder. Now I said that to 68mg (=80mm3) x14.7 = 999.6 the mg of air necessary to maintain the afr. 999.6/517.2 = 1,92 bar of pressure necessary to compress 999.6 mg of air in the cylinder. If the turbine ori holds this pressure, we can begin to moddare maps turbo giving it this limit. If we do not do a step at a time is the map we end up in 2020....and there we can star all day on the forum....

Whereas, as it says munro relying on the MAF is the best solution, according to me you can sketch out a rough estimate.
I agree that a cylinder of 400cc filled to the entire atmospheric pressure contains 517 mg of the air, if we apply to the calculation of a VE of 80%, we get about 414mg (400*0.8*1.293).
According to me it is not conceivable to burn the diesel at the ratio stechio of 14.7:1, but always according to my opinion it is more prudent to get a 17:1 maybe 18:1, however, I would try first with 17 and then I would see if the amount of smoke is acceptable.
In this case 68*17=1156mg divided for 414 damage about 2800 absolute pressure (1000+1800) always turbine permitting.

[tranky]

I look at you from above and remind you that the topic is for the beginners.. Here you go on to the advanced mechanics-although they are factors to be highly useful by pinning once you start the mapping on the ecm.
Despite the fact that I've seen the work of a professional (thanks munro) how about starting by saying for example:
- Before opening the ECM (info needed)
- let's start from map X
- the ratio of map X map Y Z..
At least to have, in light of the relationship of the maps, also a training base "certified" from which to people like me who still has trouble to start..
If you like, of course.. You are free to send me to that country.

[andrea80]

Bravo tranky...we're going to talk about already by "professionals"... Examples of units " x", that this is not..... Maybe it would be better to do as he says tranky...it would be more useful to x all..thanks

[giuseppe89]

For me it is also good because I can't Follow with difficulty the talks that among other things I follow with a lot of attention ,maybe a small study on the basics would be useful

[tranky]

Guys I am in reading for a few days since I got the notebook, to which I am installing winzozzo 7 x86 in my spare time and I have to spend 200GB of stuff at the end of the installation of the devices..
so I am with a vm for any test with the ecm on the nbook of job saw that on 8.1 doesn't run.
thank you errecinque and munro, who at the moment have highly shared info great promoting the ****llo users utonti like me.
I'll Help You !!!

[Errecinque]

I look at you from above and remind you that the topic is for the beginners.. Here you go on to the advanced mechanics-although they are factors to be highly useful by pinning once you start the mapping on the ecm.
Despite the fact that I've seen the work of a professional (thanks munro) how about starting by saying for example:
- Before opening the ECM (info needed)
- let's start from map X
- the ratio of map X map Y Z..
At least to have, in light of the relationship of the maps, also a training base "certified" from which to people like me who still has trouble to start..
If you like, of course.. You are free to send me to that country.

Look what we pulled out all this pappardella accounts because at the beginning of the topic you have rightly said to begin examining the AFR. From there, we suggested to make a map of 80 mm cubes. Then we started from the map lambda To inject 80 without smoking over due. Not to smoke you have to give him the air right then you know the turbo pressure needed. Found this as in the calculations above switing as you start the map the turbo with those data. Then you go to look for the lim iq out of drivers, to adapt them to 80mm3, it informs the ecu using the Bp of all the maps that the new iq max is 80, and adjusts the pedal to the request using the map conversion nm-iq. Of course, if you hope to make it in a day....through the forum, I repeat it is a must that one changes the map step-by-step through the info that come out reasoning all together for comparison. Time ****** of all permitting.

[Errecinque]

Bravo tranky...we're going to talk about already by "professionals"... Examples of units " x", that this is not..... Maybe it would be better to do as he says tranky...it would be more useful to x all..thanks

We are talking about the delta 1.600 joseph

[andrea80]

I fully agree... A map we can pull it outside but with these tips we can become exalted...

[munro]

Whereas, as it says munro relying on the MAF is the best solution, according to me you can sketch out a rough estimate.
I agree that a cylinder of 400cc filled to the entire atmospheric pressure contains 517 mg of the air, if we apply to the calculation of a VE of 80%, we get about 414mg (400*0.8*1.293).
According to me it is not conceivable to burn the diesel at the ratio stechio of 14.7:1, but always according to my opinion it is more prudent to get a 17:1 maybe 18:1, however, I would try first with 17 and then I would see if the amount of smoke is acceptable.
In this case 68*17=1156mg divided for 414 damage about 2800 absolute pressure (1000+1800) always turbine permitting.

if we are honest there is a way to know how much pressure it can support a turbo, but it is essential to have on hand and understand a compressor map
there is, however, a formula that from the air the hypothetical intake from the engine, we can extrapolate the iq and vice versa...
the formula is:CFM = L x rpm x VE x PR / 5660


L = Displacement
rpm = rpm
VE = volumetric efficiency
PR = pressure Ratio turbo
5660= equivalence ratio


"CFM" is a unit of measure of the anglo-saxon, "cubic feet per minute", and is used in some of the maps of the compressor.as well as lb/min which is going to pounds of air a minute.below are the conversions
CFM / 14.27 = lb / min
lb / 0,45359 = kg


however, some compressor-map are in m3 / sec then we have to convert from weight to volume.
the typical weight of the ambient air is about 1.2 kg / m3 at 20 degrees Celsius.


PR = pressure ratio with the addition of always 1 bar press atmospheric.
I repeat, however, is only a theoretical one, because here the variables that come into play are many.

so if we take for example a 6-cylinder engine 3.2 l(it is a mercedes engine, on which the stool some jobs) and we want to know how much air aspires to 4000 rpm is 1,65 bar of boost, lighthouse..


3.222 x 4000 x 96 x 2,65 / 5660 = 579,28 CFM = £ 40,59 / min = 18.41 kg / min = 0.306 kg / sec = 0.256m3 / sec
if you have under hand a compressor map you already have 2 coordinates for this transient.
now that sappaimo how much air sucks in and compresses theoretically, our engine, we can move on to diesel.


in the case of our engine that is a 6-cylinder 4-stroke(of course) we will have 3 strokes of combustion per revolution.
then at 4000 rpm we will have 4000 x 3/60 = 200 T / sec
T= injections/second.
knowing this, and knowing that the lambda we want to go to extrapolate the iq theoretical from the calculation is simple....
P. S: it is true they are calculations and concepts a bit heavy to digest, especially for those who is a novice with this stuff but if you understand these things, everything is more simple in the end.