How to recognize the maps of ecm titanium

[giuseppe89]

Delta mod lambda.rar here's the files with the different maps lambda brought to the 1000 from the mid-axis then

[Errecinque]

errecinque not to contraddirti but to understand more,I am hooked to the speech and as far as the 7000 on the bp, according to me, are not always and only iq,if you go for example to look at the map rail pressure you can also see them in the bp to 7000 but in this case we talk about pressure diesel is not the amount that you entered...that's why I was wondering how do you define that the map we are next without a driver... it gives a look at the address 1FB83A and check the bp of this map

Almost all edc16 fiat have the maps already calculated for 70mm3. The map rail pressure indicates the pressure to give in tot laps tot iq. I the driver that you indicated that the ecm gives it to me in red, and then taking another I have seen that does not convert exactly the iq, but gives you the usual percentage of load.....I don't know if what you use is more accurate

[giuseppe89]

I'm using this driver because my file is identical to another on the forum, and the ecm uses this driver for this second file,being equal I think the driver goes well for this...beyond all I did some tests to raise the rail pressure and then works at least on this we....maybe we should do other tests to see if the driver is correct all around.With regard to the values that the ecm gives us the maps diesel should be expressed in newton and then you have to convert them in mm3,wandering in search of info, I've read some post in which you spoke of a 500 nw = 100 mm3 . The report then 5=1 someone confirm if this correct?

[switing63]

Air density equal to 1mg/cm3..right?

No. The air weighs about 1.29 Kg per cubic meter so 1 mg is less than a cm3, or if you prefer a cm3 weighs 1,2928 mg. (see Wikipedia https://it.wikipedia.org/wiki/Densit%C3%A0_dell%27aria)

[switing63]

multiply cc x bars where did you get it? sure that is right? seems a little too simple....

You are sure of this. In a cylinder with a volume of 400cc can contain a maximum of 400cc of air at atmospheric pressure if doubling the pressure will contain a double volume. So if in the space of 400cc of volume, I put the 800cc of air will have a pressure of 2 bar or 2 times that of the atmosphere, if I put a 1000cc in the same volume have a pressure of 2.5 bar, and so on.

[switing63]

With regard to the values that the ecm gives us the maps diesel should be expressed in newton and then you have to convert them in mm3,wandering in search of info, I've read some post in which you spoke of a 500 nw = 100 mm3 . The report then 5=1 someone confirm if this correct?

According to me it is not correct. Among the maps contained in the ecu there is one that converts the torque request in the amount of fuel to be injected.
Let's say that they are driving a vehicle, you press on the gas pedal for about 20% of its stroke, and are at 1500 rpm. The first map that works is the one called Driver Wish, or map the pedal or a similar name, so to speak, combining the data pressure on the pedal 20% (on the map you will find 0,2*8192=1638) on the column, and 1500 rpm I will have a value of, for example 1221, which should be divided by 10, and then 122,1. This is the torque request. We skip the step of the control in detailed relief of a couple and we arrive to the map converting torque diesel. On one axis, I will find still the rpm, then 1500, on the other, I will find the values of the required torque which, for example, are 1000 and 1250 (as in our example, we requested 1221) so I'll have to interpolate the data to obtain the value of fuel to be injected.

....... 1000 1250

1500 1750 2250

then by interpolation, I get the 2192, then the quantity of diesel to be injected to fulfill the requirement of the pedal 21,92mm3.

All this to say that there is a table already calculated by the manufacturer with the calculations made to know how much diesel it takes to get a certain pair, also because it is the variable this amount depending on rpm's.
For example, the map I have an eye on myself (not being able to download others) has a column like this

....... 4000
1500 9760
1750 8890
2000 8390
2250 8315

so as you can see 83,15mm3 of fuel generates 400Nm of torque at 2250 but to have the same torque at 1500 rpm I need to 97,60, then multiplied by 5 according to me it has no sense

[munro]

you're not very far from 5nm>mm3 with your calculation 400nm/97mm3=4.2 nm-mm3...
in addition, in the ecu there is a map that subtracts nm then iq for the internal calculation of the friction is located immediately after the torque limiters and an 8x8 z axis all in negative...

[munro]

comunqueper completeness of the info in the map nm on iq,then that is the map "command iq vs time of injectors opening" always take into consideration the maximum iq relative to the maximum torque calculated in the positive...that is your iq on nm optimum calculated from the mother house

[switing63]

small clarification of the lambda value of the edc16c if you look at attentamenteun file ori and lambda 1=afr 14,5 for the diesel only at idle..with a afr of 14.5-to-diesel sfummacchia enough...already 16.5 of afr you are ok with the lambda you have to do the log to see if a given maf is there or not cut iq with a given lambda afr...

As you rightly said, even if the fuel theoretically has a stoichiometric ratio of 14.5:1 in those relationships will never burn well, and sophomore alex len chipped in like a chimney.
However, I would like to add a little of use to see if I have understood well.
Let's say that the MAF sensor will show a value of 630 mg/cycle at 2000 rpm and then trying it in the map, fumes or lamdba, the corresponding value is 1330, I'm talking about a unit EDC16c, the calculation that results is 1.33*14,5=19,285 and, therefore, if I divide 630 to 19,285 = 32,67 are already mm3 not mg of diesel oil as spiegavi in your post previous to this one that I mentioned.
All of this implies that the ratio of the air/fuel, or AFR, in reality, is not 19,285:1 as you might think, but one must keep in mind one thing or the weight of the diesel fuel injected and not its volume otherwise comparing a weight with a volume and it's like comparing potatoes with carrots.
The air we already know very well how much it weighs because the work had already been done by the MAF sensor, the fuel should calcolarcelo, and then multiplying the 32,67mm3 for 0,8325 (average between 0,820 and 0,845, which is the density that should have by law the diesel) I get about 27,2 mg that compared with the amount of air I get a AFR of 21.3.

[switing63]

you're not very far from 5nm>mm3 with your calculation 400nm/97mm3=4.2 nm-mm3...
in addition, in the ecu there is a map that subtracts nm then iq for the internal calculation of the friction is located immediately after the torque limiters and an 8x8 z axis all in negative...

Sorry if I take advantage of your expertise, but this map is also present in the EDC16c8? I still can't download the files, and what I have on hand that I'm studacchiandoci a little on is only this.