Where there are boys ?
Where there are boys ?
400cc = 400000mm3 definitely out of threshold ... have you powered the shuttle
Live ****** & you Die a HERO !
andrea for the conversion from dc to mm3 consider the factor of 0.001:1
the fattorer 0,85 said above is for AFR (I'm Sorry I made confusion above..mea culpa)
Live ****** & you Die a HERO !
I figured...I reread everything and I realized...if you come down in Puglia rivers of beer x everyone!!!!!
Guys can I join with you only in the evening,I am stuck at work..regarding the turbo pressure, it seems to me you have read that already from the original laps on the 1.7 bar boost so 2.7 in reading diagnosis...regarding the amount of diesel fuel injected I believe that they go divided for the 4 cylinder but I'm not sure
It speaks volume of the cylinder of diesel injected. If you fill the water cylinder of this delta with the piston at bdc and I are 400.000 mm3= 400 cc=0.4 liters
Now to master the calculations you need to be sure that the quantity that we want to inject, e.g. 80mm3 cycle is the total of the four cylinders or for each cylinder. Then let's start with the accounts
Sorry if I step back but how do we define if the breakpoint by 7000 units, we are providing 70 mm3? I find this value in a lot of breakpoints. I do not believe they are all related to the quantities of diesel.tonight I go through a bit map and I'll post a few screen. Because if you don't deals well this step we give the increments on who knows what the map...
The place that the stoichiometric ratio of theoretical to burn the diesel fuel is 14.5 parts of air by weight to 1 part of fuel always in weight, and which 80mm3 weigh approximately 66.6 mg the minimum amount of air is around 1 grams per cycle.
Law is the diesel norm (EN590) must have a density of between 0,820 and 0,845 Kg / litre, so if you multiplied 80*0,820=65,6 mg, while if the multiplication 80*0,845=67,6 mg that is why I said approximately 66.6, which is a middle way.
If you then multiplied the weight of 66,6*14,5=965,7 mg. I said theoretical because no Diesel engine will ever be able to burn without making smoke as a tanker the fuel to the stoichiometric ratio, then definitely 1000 mg are insufficient.