there is a mathematical calculation to do and not many people know about...in the maps of advances intervenes with the policy otherwise you do damage, and then in the single map change to all points on the basis of the duration of iq...
there is a mathematical calculation to do and not many people know about...in the maps of advances intervenes with the policy otherwise you do damage, and then in the single map change to all points on the basis of the duration of iq...
Then I want to explain a p? things to improve? many people start to learn...
suppose that at 5000 and 60 mg we have a map duration of 44? and a SOI of 27? before TDC...
we know that the duration for these 60 mg ? 44?...but how do we calculate the duration if we want to increase the mg diesel?
simple...we 44/60 = 0,733? for mg fuelI hope you'll follow...
so if you take some? inject no more? 60 mg but 65 mg make? 65 x 0,733 = 47 ?
now with 65 mg we will have a duration of 47? and a soi 30? before TDC...
the only way to try ? go on the road for now over and out![]()
Yes, but there should be a formla that you rule to the other regimini and not only at 5000 rpm
As a rule, the SOI most of 3-10? non pu? go why? pu? cause serious damage to the engine...there are so many calculations behind it and can't explain them here in two words...normally if you increase the mg should be increased as the duration and SOI...I'll give you a small example in words, so at least you can understand: get in the car turn the car starts to give gas, behold, in this moment, the ECU goes to act on the map the pedal and understands that for that 30% acceleration needs to inject 16 mg so far so simple...but the ECU for these 16 mg should decide on a SOI and a duration.
The designers of engines measure the time in degrees of rotation, that is why? you hear people talk about engine timing. The ideal point to inject the fuel ? the top dead center TDC. This ? the point where both valves are normally closed and the air ? was crushed to the maximum.
Inject 16 mg of fuel to the avr? a time (duration), why? the piston is going up and down??we need a point of BEGINNING OF INJECTION.
Suppose that 2 mg of fuel take 1 degree of rotation of the motor shaft to inject.
Assuming that the best time of injection ? 0 ? before TDC and 16mg avr? 8? to inject(DURATION).
L?injection must? start 8? btdc instead? 0? before TDC, the start of injection (SOI) must be 8 degrees before TDC so that all the fuel ? was injected from 0? BTDC![]()
so with this explanation, you understand that it's nothing to do with if 5000 or 2000 rpm and you just have to read and know how to interpret the tables and the numbers you read in the tables and this is the pu? click winols... if we have more diesel have a longer-LASTING, but for that time must go to act also on SOI easy![]()
if it can? to be useful, here are the accounts:
revolutions per minute / 60 = revolutions per second
revolutions per second / 1 000 000 = revolutions per microsecond
revolutions per microsecond * 360 degrees = degrees per microsecond
degrees per microsecond * injection duration (in microseconds) = time of injection in degrees
then I would like to raise another question
take, for example, the last column (the one that spins the most? high) and we see that it ranges from 26 to 29 degrees of advance
but of course, to inject a few mm3 of fuel it takes only a few degrees, which is absolutely not 26
in other words, we see that equality? iq, and rpm increases, it also increases the advance
then as you rule? I are two alternatives in mind: a ? put the calculated values and, in fact, distort completely the advance control to the partial, the other ? calculate only the maximum iq and then give a scalatina hand in hand down the iq...
thank you a forum must be made to learn not to keep things for himself...I of my I always say what's? or that I know![]()