fabio... I would say to continue this discussion on another topic... given that this was initially for the "injection time".
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fabio... I would say to continue this discussion on another topic... given that this was initially for the "injection time".
you're absolutely right ,I had already? opened a topic asking for an opinion for the map we can talk about the link ? this http://www.professionalchiptuning.ne...-147-JTD-115cv
Gionag ? by the time they do not you hear, did something happen? However, I floor plan I'm working on the map of the geometry, and should always be better
I had a lot to do in the way of the work... ;) all is well.
proceed as well and keep me updated !
hello and good job
how do the degrees of advance?
boys continuous here and I congratulate you for the excellent post....I just wanted confirmation...
then on my alfa jtd edc15c7 with winols maps the injection times the value of the conversion from us to degrees is:0,023437 so I find the degrees of surface that I need to inject tot mm3 of fuel at the tot bar rail.
in the maps soi I did not understand if the conversion factor is always 0,023437 or is there to do the calculation rpm*6*time(us)/1000000???
thanks....
This thing is very interesting, and I would like to understand too, so mine is not a reply but a request for explanation. The first consideration I make is that at different speed of rotation of the motor shaft at the same time, the number of degrees of rotation is not fixed but varies proportionally, that is, at 4000 rev/min 1000 us correspond to 24° in the rotation, but at 2000 rpm 1000, us correspond to only 12°, therefore, it is possible to have a conversion value is unique and equal to 0,023437 to convert the times of injection in degrees? this may not take into account the different speed of rotation of the crankshaft.Quote:
Originally Written by joker01
I personally would always calculating rpm*6*time(us)/1000000 to convert all the values of the times, in degrees, for all the maps, but as I said, I'm not sure of what and why I am asking I also enlightenment on the issue.
The second question is that the two methods give different results, or if to 4000 rpm I have a time of 950 us and use the first formula I get 4000*0.023437=22,26515°, while if I use the second (which I think is more correct) I get 4000*6*950/1000000=22,8°
These days I am continuing to study with other people on other forums, and by far, I realized that I was doing wrong.
Then map the times you need to use the conversion factor 0.976 so I find the us.
To convert to degrees, use this formula:
Rpm*6*time (us)/1000000=degrees
Instead, in the soi maps the conversion value is 0.023437 and I find the degrees.
We still expect confirmation from some expert.